The "||" function

**misplaced** · 01-09-2005

congratulations your first lesson in debugging - look through you code and find where you would get the value -32. forget about what values variables are suposed to be.

also, the inner set of {} is unnecessary

edit: scribbler beat me to this

**Shakti** · 01-09-2005

I believe your problem is right on this line: float b = ( 5/9 * a - 32 ) ;

More precisly 5/9, that is integer division and it is my bet that this is evaluated to 0, so basicly your expression looks like this:
float b = ( 0 * a - 32 ) ;

To fix you have to make sure you tell the compiler that you dont want integer division, by doing this: float b = ( 5.0f/9.0f * a - 32 ) ;

The trailing f is just to tell the compiler its a float and not a double.

Edit: awwwwww beaten!

**futurama140** · 01-09-2005

I got it, finaly, thanks

**futurama140** · 01-09-2005

actually, it was that i didnt have "()" around "a - 32", it did the multiplication first, thats why I got that answer

Code:

#include <iostream>

using namespace std;

int main()
{
    int a;
    
    cout<<"Enter Farenheit temperature to convert to Celcius:\n";
    cin>> a;
    float b = (5.0/9.0 * (a - 32) ) ;
    cin.ignore();
    {
               cout<<"Your answer is:"<< b <<"\n";
    }
         cin.get();
}

**misplaced** · 01-10-2005

Originally Posted by futurama140

actually, it was that i didnt have "()" around "a - 32", it did the multiplication first, thats why I got that answer

i doubt that. the output was -32 every time. what possible values are in the expression (n * m - 32) in which return the value -32? we know that changing 'm' does not effect the outcome, so we have (n * const value - 32). n = 5/9. if n is evalutated as an integer, then n = 0. which makes (0 * const value - 32). (0 * any number - 32) is always - 32.

**CornedBee** · 01-10-2005

Both were problem. Solving only the first part would have resulted in values that actually depend on the input, but they would have been false. Solving only the second part would have resulted in 0 always being the output instead of -32.

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